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Sorry to be asking noob questions again, and yes I did try a search. I'm looking at bidding on some equipment that contains some very large motors, like over 100 HP.
Does anyone know a rule of thumb for figuring out lbs of copper per HP? I have a rough idea, but its based on my experience with smaller motors so I'm not sure if it scales.
Tis
I've never messed with those because of the difficulty moving and processing them, but more power to ya.
They may have more value as complete units if they're any good.
Buy it and find out if you make money great if you lose money then use it as a learning experience for next time.
Read on SMF that copper amount would be approx.two thirds of horsepower.Keep us posted.GOOD LUCK
Take pictures and share what you find out after, Mike.
Tried to find where i had read that in the past posts but could not find it.I do not have any EXPERIENCE with a motor of that size,was just repeating what i have read on SMJ past posts
It was in reply to one of my posts that was stated thats about 2/3 of horsepower to copper ratio. I had some llarge 200 - 300 460 motors, I was supposed to buy, but never got a phone call back on them. The dude stated it in one of the reply's. Search my name and yall shall see.!
Hmmm I have to wonder if 2/3 is accurate. I did a 1.5 horse the other day and got just over 4 pounds. That gives a factor of 2.667 pounds per HP. I'm sure that won't work of those big monsters, they'll be 3 phase and 600 volts.
some yards pay more for larger motors check what the "as is" price, then try and figure the math!